int 1x {6 (logx) ^2+ 7logx + 2 } d x =

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Click here:point_up_2:to get an answer to your question :writing_hand:6 the value of int frac e 5 log x

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

int 1x {6 (logx) ^2+ 7logx + 2 } d x =

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

int 1/(x( 6 ( log x)^2 + 7 log x + 2) dx`

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